number systems Model Questions & Answers, Practice Test for ibps clerk mains

ibps clerk mains SYLLABUS WISE SUBJECTS MCQs

Number Systems

Average

Question :6

Out of 532 saving accounts held in a post office, 218 accounts have deposits over Rs. 10,000 each. Further, in 302 accounts, the first or sole depositors are men, of which the deposits exceed Rs. 10,000 in 102 accounts. In how many accounts the first or sole depositors are women and the deposits are up to Rs. 10,000 only?

Answer: (a)

Number of account up to Rs. 10,000

= 532 – 218

= 314 accounts.

Rest of accounts of men deposits

= 302 – 102 = 200 accounts

Number of accounts of women deposits

= 314 – 200 = 114

Question :7

If n is a natural number and n = $p_1^{x_1} p_2^{x_2} p_3^{x_3}$, where $p_1 , p_2 , p_3$ are distinct prime factors, then the number of prime factors for n is

Answer: (a)

n = $p_1^{x_1} p_2^{x_2} p_3^{x_3}$

where $P_1 , P_2$ and $P_3$ are distinct prime numbers

So no. of factors = $x_1 x_2 x_3$

Question :8

A man fills a basket will eggs in such a way that the number of eggs added on each successive day is the same as the number already present in the basket. This way the basket gets completely filled in 24 day. After how many days the basket was $1/4$ th full ?

Answer: (d)

Let x be the no of eggs already present in the basket.

Then, no. of eggs on each successive days:

x, 2x, 4x, 8x, ............ upto 24 days.

From here, we can see that number of eggs are getting doubled on each successive days.

On 24th day basket was filled completely.

∴ On 23rd day basket was filled = $1/2$

Hence, on 22nd day basket was filled = $1/2(1/2) = 1/4$

Question :9

What is the digit in the unit place of $2^51$ ?

Answer: (c)

The digit in the unit's place of $2^51$ is equal to the remainder

when $2^51$ is divided by 10.

$2^5$ = 32 leaves the remainder 2 when divided by 10.

Then $2^50 = (2^5)^10$ leaves the remainder $2^10 = (2^5)^2$

which in turn leaves the remainder $2^2$ = 4.

Then $2^51 = 2^50×2$, when divided by 10, leaves the remainder 4 × 2 = 8.

Question :10

The sum of four consecutive even numbers. A, B, C, and D is 180. What is the sum of the set of next four consecutive even numbers ?

Answer: (b)

A + A + 2 + A + 4 + A + 6 = 180

4A + 12 = 180 ⇒ A = 42.

∴ Next four consecutive even numbers are

50 + 52 + 54 + 56 = 212

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